|Force||The amount of force a hydraulic cylinder can generate is equal to the hydraulic pressure times the “effective area” of the cylinder (see cylinder selection charts).|| ||Example 1|
An RC-106 cylinder with 2.24 in2 effective area operating at 8,000 psi will generate what force?
Force = 8,000 psi x 2.24 in2 = 17,920 lbs.
An RC-106 cylinder lifting 14,000 lbs will require what pressure?
Pressure = 14,000 lbs ÷ 2.24 in2 = 6,250 psi.
An RC-256 cylinder with 5.15 in2 effective area is required to produce a force of 41,000 lbs. What pressure is required?
Pressure = 41,000 lbs ÷ 5.15 in2 = 7961 psi.
Four RC-308 cylinders each with 6.49 in2 effective area are required to produce a force of 180,000 lbs. What pressure is required?
Pressure = 180,000 lbs ÷ (4 x 6.49 in2) = 6933 psi.
Remember, since four cylinders are used together, the area for one cylinder must be multiplied by the number of cylinders used.
A CLL-2506 cylinder with 56.69 in2 effective area is going to be used with a power source that is capable of 7,500 psi. What is the theoretical force available from that cylinder?
Force = 7,500 psi x 56.79 in2 = 425,925 lbs.