**Force** | The amount of force a hydraulic cylinder can generate is equal to the hydraulic pressure times the “effective area” of the cylinder (see cylinder selection charts). | | **Example 1** An RC-106 cylinder with 2.24 in^{2} effective area operating at 8,000 psi will generate what force? **Force** = 8,000 psi x 2.24 in^{2} = 17,920 lbs.
**Example 2** An RC-106 cylinder lifting 14,000 lbs will require what pressure? **Pressure** = 14,000 lbs ÷ 2.24 in^{2} = 6,250 psi.
**Example 3** An RC-256 cylinder with 5.15 in^{2} effective area is required to produce a force of 41,000 lbs. What pressure is required? **Pressure** = 41,000 lbs ÷ 5.15 in^{2} = 7961 psi.
**Example 4** Four RC-308 cylinders each with 6.49 in^{2} effective area are required to produce a force of 180,000 lbs. What pressure is required? **Pressure** = 180,000 lbs ÷ (4 x 6.49 in^{2}) = 6933 psi. Remember, since four cylinders are used together, the area for one cylinder must be multiplied by the number of cylinders used.
**Example 5** A CLL-2506 cylinder with 56.69 in^{2} effective area is going to be used with a power source that is capable of 7,500 psi. What is the theoretical force available from that cylinder? **Force** = 7,500 psi x 56.79 in^{2} = 425,925 lbs. |